Jiali intelligent control

One, No flashing, low output voltage, can not carry the load

This kind of defect is mainly excluded from the bad cell (the cell originally has no voltage or low voltage). If the cell is bad, the self-consumption of the protection board should be checked to see if the self-consumption of the protection board is too large and the cell voltage is low. Assuming that the cell voltage is normal, it is because the entire circuit of the protection board is blocked (components are soldered, false soldered, FUSE is bad, the internal circuit of the PCB board is blocked, the via is blocked, MOS, IC damage, etc.).

The specific analysis process is as follows:

(1) Connect the black test lead of the multimeter to the negative electrode of the cell, the red test lead to the two ends of the FUSE and R1 resistors, the Vdd, Dout, Cout terminals of the IC, and the P+ terminal (assuming the cell voltage is 3.8V), and analyze it segment by segment. These checkpoints should all be 3.8V. If not, there is a problem with this circuit.

1. The voltage at both ends of the FUSE has changed: check whether the FUSE is turned on. If the lead is the internal circuit of the PCB board, there is a problem with the FUSE (bad incoming material, overcurrent damage (MOS or IC control failure), There is a problem with the material (the FUSE is burned out before the MOS or IC operates), then short the FUSE with a wire and continue to analyze it later.

2. The voltage across the R1 resistor has changed: check the R1 resistance value. If the resistance value is abnormal, it may be a virtual welding and the resistor itself cracks. If there is no abnormality in the resistance value, there may be a problem with the internal resistance of the IC.

3. The voltage of the IC inspection terminal has been changed: the Vdd terminal is connected to the R1 resistor. The Dout and Cout terminals are abnormal, because the IC is soldered or damaged.

4. If there is no change in the previous voltage, check that the voltage between B- and P+ is abnormal, because the positive via of the protection board is blocked.

(2) The red test lead of the multimeter is connected to the positive pole of the battery cell. After activating the MOS tube, the black test lead is connected to the 2, 3, 6, 7 pins of the MOS tube, and the P- terminal in turn.

1. If the voltage of MOS tube 2, 3, 6, 7 is changed, it indicates that the MOS tube is abnormal.

2. If the voltage of the MOS tube is unchanged and the voltage of the P- terminal is abnormal, it is because the negative hole of the protection board is blocked.

Two, Short circuit without protection

1. There is a problem with the VM terminal resistance: a multimeter can be used to connect a test lead to the IC2 pin, and a test lead to the MOS pin connected to the VM end resistance to confirm its resistance value. Check whether the resistor is soldered to the IC and MOS pins.

2. IC and MOS abnormality: Because the over-discharge protection and over-current and short-circuit protection share a MOS tube, if the short-circuit abnormality is due to a problem with the MOS, this board should have no over-discharge protection function.

3. The above are faults under normal conditions, and there may also be short-circuit abnormalities caused by poor IC and MOS equipment. For example, in the BK-901 that appeared earlier, the delay time in the IC whose model is '312D' is too long, causing the MOS or other components to be damaged before the IC performs corresponding action control. Note: The easiest and direct way to confirm whether the IC or MOS is malfunctioning is to replace the suspected components.

Three, Short circuit protection without self-recovery

1. The IC used in the design originally did not have a self-recovery function, such as G2J, G2Z, etc.

2. The short-circuit recovery time set by the instrument is too short, or the load is not removed during the short-circuit inspection. For example, after short-circuiting the short-circuit test leads with the multimeter voltage range, the test leads are not removed from the test end (the multimeter is equivalent to a load of several megabytes).

3. Leakage between P+ and P-, for example, there is rosin with impurities between the pads, yellow glue with impurities or the capacitance between P+ and P- is broken down, and the breakdown between ICVdd and Vss is broken. (The resistance value is only a few K to several hundred K).

4. Assuming that there is no problem with the above, maybe the IC is broken down, you can check the resistance between the pins of the IC.

Four, Large internal resistance

1. Because the internal resistance of MOS is relatively stable, and the internal resistance is large, the first suspect should be the components whose internal resistance is relatively simple to change, such as FUSE or PTC.

2. Assuming that the resistance value of FUSE or PTC is normal, the resistance value of the via hole between the P+ and P- pads and the component surface may be detected according to the structure of the protection board. There may be micro-breaks in the via hole, and the resistance value is relatively large.

3. Assuming that there are no problems with the above, it is necessary to suspect whether the MOS is abnormal: first, confirm whether there is a problem with the welding; second, check the thickness of the board (whether it is simply bent), because bending may cause abnormal welding of the pins; then connect the MOS tube Put it under the microscope to observe whether it is broken; after all, use a multimeter to check the resistance of the MOS pin to see if it is broken down.

Five, ID disorder

1. The ID resistor itself is abnormal due to virtual welding, cracking or due to the failure of the resistance material: the two ends of the resistor can be re-welded. If the ID is normal after re-welding, the resistance is virtual welding. If it cracks, the resistance will be cracked after re-welding. open.

2. The ID via is not conducting: You can use a multimeter to check both ends of the via.

3. There is a problem with the internal circuit: scrape off the solder resist paint to see if the internal circuit is disconnected or short-circuited.